Hi,
I'm having troubles to understand the example of PCA. How is the simplification of eq 2.55 to eq 2.56?
Eq 2.55:
c^* = argmin_c||x-g(c)||^2_2
Eq 2.56:
(x-g(c))^T(x-g(c))
Thanks for your help,
Cheers.
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Hi,
I'm having troubles to understand the example of PCA. How is the simplification of eq 2.55 to eq 2.56?
Eq 2.55:
Eq 2.56:
Thanks for your help,
Cheers.