thank you

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can someone please help in this question

if have two states dp[i][0] mean ith not selected

dp[i][1] means ith selected

and i have also added code to handle circular condition

#include<bits/stdc++.h>using namespace std;static int arr[10000000],dp[10000000][2];int main(){int t,i,j,k,l,m,n;scanf("%d",&n);for(i=0;i<n;i++){scanf("%d",&arr[i]);}dp[0][1]=arr[0];dp[0][0]=0;dp[1][1]=arr[1];dp[1][0]=dp[0][1];

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sort array

then for each i bw o to n-1 do log(n) by binary search

i.e. for indx i , find first smallest index j, such that arr[i]+arr[j]>=k

n-j (approx +-1 ) is variation of the that ith indx

add for all i

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